2) Answer;
The equation shows that the mass of the products is always equal to that of the reactants.
Step-by-step explanation;
- Einstein's equation E=mc²; where the E stands for energy and the m stands for mass, a measurement of the quantity of matter. From the equation energy and matter are interchangeable. Energy is equivalent to matter multiplied by the speed of light squared.
- The grand total remains constant, but energy regularly changes form into matter and matter into energy. Einstein's equation gave rise to various advances in technology technological, from nuclear power and nuclear medicine to the inner workings of the sun. The equation tells us that matter and energy are one.
3. Answer;
The amount of energy released in nuclear reactions is so much larger than the energy released in chemical reactions
Explanation;
- Nuclear reactions such as nuclear fission and fusion release much larger energy as compared to chemical reactions because tremendous amounts of energy is released at one time.
- In nuclear reactions, for example nuclear fission, when an atom is split inside a nuclear power plant or an atomic bomb, the resulting energy releases at the speed of light.
- E = mc2 is the key to understanding why and how energy is released in nuclear reactions. The equation relates to the reductions in mass and the numerous production of energy that occur in nuclear reactions.
4. Answer:
The above statement is TRUE
Step-by-step explanation;
- The Law of conservation of mass states that during any physical or chemical change, the total mass of the products is equal to the total mass of reactants provided.
- Nuclear reactions violate the law of conservation of mass. For instance the nuclear fusion reactions occurring in the sun as a result of fusion between hydrogen nuclei causing formation of helium nuclei. The conservation of mass is not observed as some mass is converted to energy.
5. Answer;
The statement "In both nuclear fission and nuclear fusion reactions, energy is converted to mass" is FALSE
Step-by-step explanation;
- Instead, mass is converted to energy during both nuclear fission and nuclear fusion.
- Nuclear fission and nuclear fusion are the two types of nuclear reactions. Nuclear fusion involves the combining of two small nuclei to form a larger nuclei coupled with the release of energy. Nuclear fission on the other hand involves the splitting of a heavy larger nuclei to yield smaller nuclei and is also coupled with the release of energy.
- In nuclear fission, the resultant products have a slightly smaller nuclear mass as compared to heavy nucleus. This difference in mass is because some mass is converted to energy during the fission.
- Similarly in nuclear fusion some of the mass of the initial nuclei is converted into energy in the form of heat or light.
6. Answer;
The above statement is FALSE
Step-by-step explanation;
- In nuclear reactions some mass is converted into energy. The mass "lost" is NOT used to convert energy into mass.
- In nuclear fission, the resultant products have a slightly smaller nuclear mass as compared to heavy nucleus. This difference in mass is because some mass is converted to energy during the fission.
- Similarly in nuclear fusion some of the mass of the initial nuclei is converted into energy in the form of heat or light.
7. Answer;
=2.736 * 10^15 J
Solution;
E = mc² ; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).
Mass = 0.0304 kg
E = (0.0304)(3×10^8)²
Energy = 2.736 × 10^15 J
oules
8. Answer;
= 2.7 × 10¹⁷ Joules
Solution;
E = mc²; where E is the energy in joules, m is the mass in kg, and c is the speed of light (3.0 10^8 m/s).
Mass = 3 kg
E = 3 kg × (3 × 10⁸ m/s)²
E = 3 kg × 9 × 10¹⁶ m/s²
E = 27 × 10¹⁶ joules
Energy = 2.7 × 10¹⁷ joules
9. Answer;
m = 3.3 × 10³ Kg
Solution;
E = mc² ; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).
Energy = 3 × 10^20 Joules
Thus; 3 × 10²⁰ = m × (3 * 10^8)²
m = 3 × 10²⁰ / 9 × 10^16
m = 3.3 × 10³Kg
10. Answer;
E = 2.7 × 10⁻¹¹ Joules
Solution;
E = mc²; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).
Mass = 3 × 10^-18 kg
E = (3 × 10⁻²⁸)(3 × 10⁸)²
E = 3 × 10⁻²⁸ × 9 × 10¹⁶
E = 27 × 10⁻¹²
E = 2.7 × 10⁻¹¹ Joules
11. Answer;
= 2. 75x 10^-11 Joules
Solution
Given that; 1 amu= 1.66 x 10-27 kg; 1 J = 1 kg m2/s2)
Mass = 0.184 x 1.66 x10^-27
= 3.054 x 10^-28 kg
E = mc^2
E = 3.054 x 10^-28 kg x (3.0 x10^8 m/s)^2
= 3.054 x 10^-28 kg x 9.0 x 10^16
Energy = 2. 75x 10^-11 Joules