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How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2?

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The balanced equation for the reaction when hydrogen and nitrogen reacts with each other and Ammonia NH₃ is formed as a result is:

3H₂(g) + N₂(g) --> 2NH₃(g)

The equation shows when 3 moles of hydrogen reacts 2 moles of ammonia is formed.

3 moles of H₂……….2 moles of NH₃

So when there is 24 moles of hydrogen, no. of moles of NH₃ = 24 x 2/3 = 8 x 2 = 16 moles

Thus, 16 moles of NH₃ is formed.

User Pradeep Kumar HK
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