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What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)? y − 1 = −2(x − 4) y − 1 = 2(x + 2) y − 13 = −2(x + 2) y − 13 = 2(x + 4)
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Apr 25, 2018
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What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)? y − 1 = −2(x − 4) y − 1 = 2(x + 2) y − 13 = −2(x + 2) y − 13 = 2(x + 4)
Mathematics
high-school
Billfredtom
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Find the slope first m = (13 - 1) / (4 - -2) = 12/6 = 2
Use y = mx + b and one of those points for x and y
13 = 2(4) + b
13 = 8 + b
b = 5
Equation : y = 2x + 5
Yurii Melnychuk
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Apr 27, 2018
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Yurii Melnychuk
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point slope form: y - y1= m (x-x1)
Find the slope: y1-y2/x1-x2 = 13-1/4-(-2) = 12/6 reduce it: 2
So the slope is 2
Choose one of the points: (4,13), (x1,y1)
The equation is y - 13 = 2 (x - 4)
Greymatter
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May 1, 2018
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Greymatter
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