Question

How many liters of a 0.75 M solution can be made with 75 grams of lead (ll) oxide?

Answer 1

To make a 0.75 M solution with 75 grams of lead (II) oxide, first calculate the moles of PbO, which are 0.336 moles. Then, divide the moles by the desired molarity to find the volume, resulting in approximately 0.448 liters of the solution.

Step-by-step explanation:

To determine how many liters of a 0.75 M solution can be made with 75 grams of lead (II) oxide (PbO), we first need to calculate the molar mass of PbO. The molar mass of PbO is the sum of the molar masses of Pb (207 g/mol) and O (16 g/mol), resulting in 207 g/mol + 16 g/mol = 223 g/mol. Next, we calculate the moles of PbO using the formula:

moles = mass (g) / molar mass (g/mol)

Substituting into the formula gives us:

moles = 75g / 223 g/mol = 0.336 moles of PbO

Since the desired concentration is 0.75 M (moles per liter), we can find out the volume of the solution:

Volume (L) = moles / concentration (M)

Volume = 0.336 moles / 0.75 M = 0.448 L

Therefore, with 75 grams of lead (II) oxide, one can prepare approximately 0.448 liters of a 0.75 M solution.

Answer 2

Step 1

Molarity is defined as:

Molarity (M or mol/L) = Moles of lead (II) oxide/Volume of solution (L)

Molarity = mass of lead (II) oxide/molar mass of lead (II) oxide x volume (L) (1)

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Step 2

The molar mass of PbO = 223 g/mol

PbO = lead (ll) oxide

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Step 3

Data provided:

Molarity = 0.75 M

Mass of PbO = 75 g

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Step 4

Procedure:

The volume of the solution is cleared from (1):

Volume (L) = mass PbO/(molar mass PbO x Molarity)

Volume (L) = 75 g/(223 g/mol x 0.75 mol/L) = 0.45 L approx.

Answer: Volume = 0.45 L