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the length of a rectangle is 1 cm more than twice it's width. of area of the rectangle is 21 cm^2 then what are the dimensions?

the length of a rectangle is 1 cm more than twice it's width. of area of the rectangle-example-1

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You are given a rectangle and are told that the length is 1 cm more than twice the width of the rectangle. The area of the rect. is also given, and is 21 cm^2.

Find the length and width. To do this, represent the length by y and the width by x. Then "1 cm more than twice the width" comes out to y=2x+1 (cm).

Since the area of a rect. is equal to the product of its length and width,

x(2x+1)=21 cm^2. Multiply out x(2x+1). show your work. Next, subtract 21 from both sides. Write your algebraic expression on the left side as a quadratic equation in standard form.

Solve this quadratic equation for x. Recall that x (in cm) will represent the width of the rect., and y=2x+1 (in cm) will repr. the length.
User Alexey Blinov
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