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14 votes
14 votes
Find the measure of each of the other six angles

User Mike Fielden
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1 Answer

15 votes
15 votes

The measure of angle 1 is 71º, we can find this, because angle 1 and angle x form a straight line of 180º, so 180º - 109º = 71º

The measure of angle 2 is also 71º, we can use the vertical angles propierty, then m∠1 = m∠2

The measure of angle 3 is 109º, we can use again the vertical angles theorem to find that m∠x = m∠3

Themeasure of angle 7 is 109º. We need to use the alternating exterior angles theorem. Since angle x and angle 7 are not between the parallel lines they're exterior angles; and since they're on opposite sides of the transversal line, they're alternates. Then the theorem says that m∠x = m∠7

The measure of angle 6 is 71º, again we're using the fact that angle 7 and angle 6 forms a straight line, then m∠6 = 180º - 109º = 71º

Now we can find the lasts two measures using the vertical angles theorem.

The measure of angle 5 is 71º, because m∠6 = m∠5

The measure of angle 4 is 109º, because m∠7 = m∠4

User Zin Win Htet
by
3.0k points
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