Final answer:
The sum of the expression 4(m+2)+3(6m-4) is found by distributing the multiplication and combining like terms, which results in 22m - 4.
Step-by-step explanation:
To find the sum of the expression 4(m+2)+3(6m−4), we will first apply the distributive property to remove the parentheses. This involves multiplying the factor outside the parentheses by each term inside the parentheses. Let's do this step by step:
- Multiply 4 by both m and 2 in the first part: 4⋅m + 4⋅2, which simplifies to 4m + 8.
- Multiply 3 by both 6m and −4 in the second part: 3⋅6m + 3⋅(−4), which simplifies to 18m − 12.
Now we combine the like terms (terms with the variable m) and constants:
- Add the coefficients of m: 4m + 18m = 22m.
- Add the constants: 8 − 12 = −4.
Putting it all together, the sum of the expression is 22m − 4.