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How many moles of nitrogen dioxide, NO2, are required to produce 3.56 mol of nitric acid?
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How many moles of nitrogen dioxide, NO2, are required to produce 3.56 mol of nitric acid?

User Bogd
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Considering the reaction:
3NO₂ + H₂O → 2HNO₃ + NO

To produce 3.56 moles of nitric acid, we require:
3.56 x 3/2 moles of NO₂
Moles of NO₂ = 5.34 moles of NO₂
User Aaron McGuire
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