Question

Used two equations in two variables to solve the application.A 60 m pass around the rectangular garden. The width of the garden is 2/3 its length. Find the area in meters squared.

Answer 1

From the data provided, we can conclude:

The perimeter of the rectangle is 60m, so:

`60=2w+2l_{\text{ }}(1)`

Where:

w = width

l = length

The width of the garden is 2/3 its length, therefore:

`w=(2)/(3)l_{\text{ }}(2)`

Replace (2) into (1)

`60=2((2)/(3)l)+2l`

Solve for l:

`\begin{gathered} 60=(4)/(3)l+2l \\ 60=(10)/(3)l \\ l=(180)/(10) \\ l=18 \end{gathered}`

Replace l into (2):

`\begin{gathered} w=(2)/(3)(18) \\ w=12 \end{gathered}`