32.7k views
5 votes
How do I graph 5x+2y+8=0?

1 Answer

5 votes
You have to rearrange the equation so that it's in slope intercept form, y=mx+b. You have to move 5x and 8 to the other side of the equal sign:
2y=-5x-8

Then divide both sides by 2:
y=-5/2x-4

In y=mx+b, m is slope and b is the y-intercept. So, the slope is -5/2 and the line intersects the y-axis at the point (0,-4).

The easiest way to graph the equation is to graph the y-intercept first. Then, because the slope is -5/2, and slope is rise/run, you go DOWN 5 units and to the right 2 units from (0,-4). You repeat this multiple times. To get the points on the left side of the y-axis, you go UP 5 units and left 2 from (0,-4). Repeat.
User Michael Vescovo
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories