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5 votes
The point (x,sqrt7/3) in the second quadrant corresponds to angle θ on the unit circle. *blank*θ=3/sqrt of 7 *blank*θ=sqrt of 7/3 What are the blanks?

User Mych
by
6.8k points

2 Answers

3 votes
Since the point lies on the unit circle, its distance from the origin is 1.

So,


\sin\theta=\frac{\frac{\sqrt7}3}1=\frac{\sqrt7}3

which means


\csc\theta=\frac1{\sin\theta}=\frac3{\sqrt7}
User John Galambos
by
6.2k points
6 votes

Answer:

csc (θ) = 3/ sqrt(7)

sin(θ)= sqrt(7)/3

Explanation:

The point (x,sqrt7/3) in the second quadrant corresponds to angle θ on the unit circle.

The point (x,y) on the graph represents (cos theta, sin theta)

Given point is
(x,(√(7) )/(3) )

cos(θ) =x

sin(θ)= sqrt(7)/3

csc (θ) is the inverse of sin(θ)

So csc (θ) = 3/ sqrt(7)

User MrSnrub
by
6.8k points
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