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Help its geometry...............

Help its geometry...............-example-1
User Gasche
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m GH = 57''

________


tan 39° = opposite / adjacent

tan 39° = m GH / m HJ

tan 39° * m HJ = m GH

m HJ = m GH / tan 39°

m HJ ≈ 57'' / 0.810

m HJ ≈ 70.4'' <——— measure of the segment HJ

________


sin 39° = opposite / hypotenuse

sin 39° = m GH / m GJ

sin 39° * m GJ = m GH

m GJ = m GH / sin 39°

m GJ = 57'' / 0.629

m GJ ≈ 90.6'' <——— measure of the segment GJ

________


So the perimeter is

p = m GH + m HJ + m GJ

p = 57'' + 70.4'' + 90.6''

p = 218'' <——— this is the answer.


I hope this helps. =)


Tags: perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry

User Pod Mays
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