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Given the quantities a= 9.7 m, b= 4.2 s, c= 69 m/s, what is the value of the quantity d = a^3/(cb^2)?

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Final answer:

The quantity d = a^3/(cb^2) given the values a= 9.7 m, b= 4.2 s, c= 69 m/s is calculated as 0.750 m^2/s (to three decimal places).

Step-by-step explanation:

The student is asking for the calculation of a quantity d where d = a^3/(cb^2) given that a= 9.7 m, b= 4.2 s, and c= 69 m/s. To compute this, we will follow these steps:

  1. Cube the value of a (raise a to the power of 3).
  2. Square the value of b (raise b to the power of 2).
  3. Multiply the value of c with the squared value of b.
  4. Divide the cubed value of a by the product from step 3 to get the value of d.

Carrying out these calculations:

  1. a^3 = 9.7^3 = 912.673 m^3.
  2. b^2 = 4.2^2 = 17.64 s^2.
  3. cb^2 = 69 m/s * 17.64 s^2 = 1217.16 m·s.
  4. d = a^3 / (cb^2) = 912.673 m^3 / 1217.16 m·s = 0.750 m^2/s (rounded to three decimal places).

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