Question

Iliana multiplied 3p – 7 and 2p^2 – 3p – 4. Her work is shown in the table.

Which is the product?

6p^3 + 23p^2 + 9p + 28
6p^3 – 23p^2 – 9p + 28
6p^3 – 23p^2 + 9p + 28
6p^3 + 23p^2 – 9p + 28

Answer 1

Answer: the answer is c

Explanation:

Answer 2

Option third is correct that is
`6p^3-23p^2+9p+28`

Explanation:

We have been given two expression
`(3p-7)` and
`(2p^2-3p-4)`

multiplication is to be done simplify the expressions by opening the parenthesis we will get

`\left(3p-7\right)\left(2p^2-3p-4\right)`

`\Rightarrow`
`3p\cdot \:2p^2+3p\left(-3p\right)+3p\left(-4\right)+\left(-7\right)\cdot \:2p^2+\left(-7\right)\left(-3p\right)+\left(-7\right)\left(-4\right)`

After simplification we will get

`\Rightarrow3\cdot \:2p^2p-3\cdot \:3pp-3\cdot \:4p-7\cdot \:2p^2+7\cdot \:3p+7\cdot \:4`

Further simplification will give the final result

`\Rightarrow6p^3-23p^2+9p+28`