Question

Factor completely: 3x'2 + 6x + 3a. (3x + 1) (x + 6)b. (3x + 3) (x + 1)c. 3(x + 1)'2d. 3(x + 1) (x-1)the 2s with the commas are exponents

Answer 1

3x^2 + 6x + 3

a= 3

b= 6

c = 3

Find the product of a and c

3x3 = 9

Now, find a product that equal 3x3 and equals be when added

b= 6

3+3 = 6

3x3= 9

Rewrite the expression with the new numbers taking the middle place:

3x^2 +3 x+ 3x +3

Isolate terms and factor out the greatest common factor:

(3x^2 +3 x) + (3x +3)

3x ( x+1) + 3 (x+1)

Factor out x+1 and rewrite:

(3x+3) (x+1)