Question

Select the two values of x that are roots of this equation.3x² + 1 = 5xA. x =5+√13x = 5+√136☐ B. x =5-√136□ C. x=-1-√59X6D. X =-1+√596

Answer 1

3x^2 + 1 = 5x

3x^2 - 5x + 1 = 0

quadratic formula

`x=-(b\pm√(b^2-4ac))/(2a)`

where ax^2 + bx + c = 0

so

`x=(5\pm√(-5^2-4(3)(1)))/(2(3))`
`x=(5\pm√(25-12))/(6)`

You can see that the 25 - 12 = 13 so the answers are A and B