Question

Graph a line that contains that point (-7,-4) and has a slope of -2/3

Answer 1

`y=-(2)/(3)x-(26)/(3)`

Explanation:

Equation of straight line in point slope form is given as

`(y-y_1)=m(x-x_1)`

Here

`(x_1, y_1)=(-7,-4) \ and \ m=-(2)/(3)`

Therefore,

`(y+4)=-(2)/(3)(x+7)`

Graph of equation is attached