Question

The velocity of an object increases from -10 m/s to -15 m/s in 2.0 s. What is the average acceleration of the object?

Answer 1

Average acceleration is given by:

a_average = V2 - V1/dt = -15 +10/2 = -2.5 m/s^2

Answer 2

`a=-2.5 \ m/s^2.`

Step-by-step explanation:

It is given that.

Initial velocity,
`v_i=-10\ m/s`.

Final velocity,
`v_f=-15 \ m/s`.

Also, time taken during the process,
`t=2.0 \ s`.

So, average acceleration, a is given by:

`a=(v_f-v_i)/(t)`

Putting all the given values in above equation.

`a=(-15-(-10))/(2) \ m/s^2=-2.5 \ m/s^2.`

Hence, it is the required solution.