Question

For the reaction P4+6Cl2 yields 4pcl3, determine how many moles of Cl2 would be needed to react with 3 moles of P4 to entirely use up all phosphorous.

Answer 1

1 mole of P4 need to react with 6 moles

1 => 6
3 => x

x = 3 * 6/ 1= 18 moles

Answer 2

`n_(Cl_2)=18molCl_2`

Step-by-step explanation:

Hello,

In this case, the undergoing chemical reaction is:

`P_4+6Cl_2-->4PCl_3`

In such a way, if 3 moles of P₄ are reacting, the needed moles of Cl₂ to completely consume them turn out:

`n_(Cl_2)=3molP_4*(6molCl_2)/(1molP_4)\\n_(Cl_2)=18molCl_2`

This is done by realizing that 1 mole of P₄ needs 6 moles of Cl₂ to take the reaction to completion.

Best regards.