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Suppose the probability that it rains in the next two days 1/3 for tomorrow and 1/6"for the day after tomorrow. What is P(rain tomorrow, then rain the day after tomorrow)?

A.1/2
B.1/18
C.2/9
D.1/9

2 Answers

1 vote
This events are separate , so the probability of both of which combined is the product of them.

Let P(A) rain tomorrow event
P(B) rain after tomorrow event

P(A) = 1/3

P(B) = 1/6

P(A in B) = P(A) * P(B) = 1/3 * 1/6= 1/18

Choice: (B)
User Ali Raza
by
6.8k points
1 vote

Answer:


(1)/(18)

Explanation:

Probability that it rains tomorrow P(A)=
(1)/(3)

Probability that it rains day after tomorrow P(B)=
(1)/(6)

So, P(rain tomorrow, then rain the day after tomorrow)


P(A) * P(B)


(1)/(3) * (1)/(6)


(1)/(18)

Hence P(rain tomorrow, then rain the day after tomorrow) is
(1)/(18)

So, Option B is correct.

User Chris Ian
by
8.8k points

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