Question

If the weight of an object is greater than the buoyant force acting on it, it will sink. What is the weight of a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g.

Hint: Convert mass to weight using F = mg, where mass is in kilograms and g = 9.80 m/s2.
a)213 g
b)0.213 kg
c)2.09 N
d)2,090 N

Answer 1

Weight of the block of iron is 2.09 N

Step-by-step explanation:

If the weight of an object is greater than the buoyant force acting on it, it will sink. The dimension of the box is 3.00 cm x 3.00 cm x 3.00 cm.

Mass of the box, m = 213 g

Converting it into kg, m = 0.213 kg

Using second law of motion, F = W = mg

W = 0.213 kg × 9.8 m/s²

W = 2.0874 N

or W = 2.09 N

Hence, the correct option is (c) " 2.09 N ".

Answer 2

Answer: option c) 2.09 N

Step-by-step explanation:

The weight of a block of iron with the dimensions 3.00 cm × 3.00 cm × 3.00 cm, and that has a mass of 213 g may be calculated using the given hint: convert mass to weight using F = mg, where mass is in kilograms and g = 9.80 m/s².

• First, convert the mass in grams to kilograms: 213 g × 1 kg / 1000 g = 0.213 kg

• Weight = F = mg = 0.213 kg × 9.80 m/s² = 2.0874 N

• Round to three signficant figures: 2.09 N