Question

-87, -70, -27, -36,...a(n)= 17n - 10432nd term

Answer 1

We have the arithmetic progression given by

`a_n=17n-104`

if n = 1 we have the first term, n = 2 the second one and, so on, to find the 32nd term we just do n = 32, therefore

`\begin{gathered} a_(32)=17\cdot32-104 \\ \\ a_(32)=544-104 \\ \\ a_(32)=440 \end{gathered}`

The 32nd term is 440.