132k views
2 votes
A circle has a diameter with endpoints of (2, -8) and (6, 4). What is the center of the circle?

2 Answers

5 votes
Diameter = √(y2-y1)² + (x2 - x1)²
d = √(4-(-8))² + (6-2)²
d = √12² + 4²
d = √144 + 16
d = √160

In short, Your Answer would be √160 or 12.65

Hope this helps!
User Chiducaf
by
8.1k points
4 votes
The length of the diameter is (4,12)
The center is (4, -2)
User Alan Delimon
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories