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A circle has a diameter with endpoints of (2, -8) and (6, 4). What is the center of the circle?
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2 votes
A circle has a diameter with endpoints of (2, -8) and (6, 4). What is the center of the circle?

User Pieter Alberts
by
8.7k points

2 Answers

5 votes
Diameter = √(y2-y1)² + (x2 - x1)²
d = √(4-(-8))² + (6-2)²
d = √12² + 4²
d = √144 + 16
d = √160

In short, Your Answer would be √160 or 12.65

Hope this helps!
User Chiducaf
by
8.1k points
4 votes
The length of the diameter is (4,12)
The center is (4, -2)
User Alan Delimon
by
8.2k points
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