M^1/3 divided by m^1/5 m^1/5 divided by m^1/3 m^1/3*m^1/5 (m^1/3)^1/5 (m^1/3m^1/5)^0

asked Oct 26, 2018 173k views

3 votes

M^1/3 divided by m^1/5

m^1/5 divided by m^1/3

m^1/3*m^1/5

(m^1/3)^1/5

(m^1/3m^1/5)^0

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3 votes

M^1/3 divided by m^1/5 = m^2/15

m^1/5 divided by m^1/3 = 1/ m^2/15

m^1/3*m^1/5 = m^8/15

(m^1/3)^1/5 = m^1/15

(m^1/3m^1/5)^0 =1

Tan Rezaei answered Oct 30, 2018

7.6k points

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