Question

You are running a fuel economy study. one of the cars you find where blue

Answer 1

Step-by-step explanation:

For Blue Car:

Distance = 33 & 1/2 miles

Gasoline = 1 & 1/4 gallons

For Red Car:

Distance = 22 & 2/5 miles

Gasoline = 4/5 gallon

To determine the rate unit rate for miles per gallon for each car, we use the following formula:

`Unit\text{ Rate = }\frac{\text{Distance}}{\text{Gasoline consumption}}`

First, we find the unit rate for blue car:

`\begin{gathered} \text{Unit Rate=}\frac{33\text{ }(1)/(2)\text{ miles}}{1\text{ }(1)/(4)\text{ gallons}} \\ \end{gathered}`

Convert mixed numbers to improper fractions: 33 & 1/2 = 67/2 and 1 & 1/4 = 5/4

`\begin{gathered} \text{Unit Rate = }((67)/(2))/((5)/(4)) \\ \text{Simplify and rearrange:} \\ =(67(4))/(2(5)) \\ \text{Calculate} \\ =\frac{134\text{ miles}}{5\text{ gallon}}\text{ } \\ or\text{ }26.8\text{ miles/gallon} \end{gathered}`

Next, we find the unit rate for red car:

`\begin{gathered} \text{Unit Rate = }(22(2)/(5))/((4)/(5)) \\ \text{Simplify and rearrange} \\ =((112)/(5))/((4)/(5)) \\ =(112(5))/(5(4)) \\ \text{Calculate} \\ =28\text{ miles/gallon} \end{gathered}`

Therefore, the car that could travel the greater distance on 1 gallon of gasoline is the red car.