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21 votes
Need help asap look in file attached

Need help asap look in file attached-example-1
User Yanpas
by
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1 Answer

21 votes
21 votes

Answer:

length: 21 cm

width: 16 cm


Explanation:


. A rectangle has two lengths and two widths, or two sides that are vertical (up and down) and two sides that are horizontal (left and right)


. In order to find the perimeter we must add up all four side lengths.


. You can find the perimeter of a rectangle by adding the length and the width then multiplying by 2, because there are two of each side length.


P = 2(l+w)


In the question the perimeter is given, which is 74.


We can divide 74 by 2 so that we can find the sum of the length and width.


74/2 = 37

l + w = 37


In the question is states that the length is 5 inches longer than the width.


l = (5 + w)


There are two widths and two lengths in a rectangle, the measurement of the two lengths is 5 inches longer than the two widths.


5 + w + w = 37

5 + 2w = 37


Now that we have our equation we can solve for w, or the width.


1. Move the term containing the variable to the left


5 + 2w = 37

2w + 5 = 37


2. Subtract 5 from both sides of the equation, the opposite of adding 5

2w + 5 = 37

2w + 5 - 5 = 37 - 5

2w = 32


3. Divide by 2 in both sides of the equation, the opposite of multiplying 2


2w = 32

2w/2 = 32/2


4. Cancel out the 2s on the left, but leave the x

2w/2 = 32/2

w = 16

So, now that w, or the width = 16, we can find the length:

l = 5 + w

l = 5 + 16

l = 21


You can check your answer by plugging in our values into the original perimeter formula:


P = 2(l+w)

P = 2(21 + 16)

P = 2(37)

P = 74, so my answer is correct, because 74 is the perimeter given in the question.



User Gargantuan
by
2.7k points
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