Question

Write the complete nuclear equation for the bombardent of a 14N atom with an α particle to yield 17O. Show the atomic number and mass number for each species in the equation.

Answer 1

The nuclear equation for the bombardment of a 14N atom with an α particle to yield 17O is _{7}^{14}N + _{2}^{4}He \rightarrow _{8}^{17}O + _{1}^{1}H, with both mass and atomic numbers conserved.

Step-by-step explanation:

To create the complete nuclear equation for the bombardment of a 14N atom with an α particle to yield 17O, we need to follow the conservation of mass and atomic numbers. The α particle is a helium nucleus, which has an atomic number of 2 and a mass number of 4. The nitrogen (14N) has a mass number of 14 and an atomic number of 7. After the bombardment, oxygen (17O) is produced which has a mass number of 17 and an atomic number of 8. The nuclear equation for this reaction is: _{7}^{14}N + _{2}^{4}He \rightarrow _{8}^{17}O + _{1}^{1}H As you can see, both the atomic numbers and the mass numbers are balanced on each side of the equation. The sum of the atomic numbers is 7 + 2 = 8 + 1, and the sum of the mass numbers is 14 + 4 = 17 + 1.

Answer 2

14N + α → 17O + β- i think that is what it is if not tell me