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Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5
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Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

User Yoani
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Set equal to eachother:
2x+5=x^2-x-5
0=x^2 - 3x -10
0=(x-5)(x+2)
x = -2, 5
User Masjum
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