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What are the solutions of the equation: z^2 - 12z + 36 = 0? 

A. -6, 6
B. 6, 6
C. 6, -6
D. -6, -6

User Stavros
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1 Answer

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Factor by groups
(Z^2 -6z) (-6z+36)
GCF 1st binomial is z
GCF of 2nd binomial is -6
(z-6)(z-6)
Solutions
6,6
User Miguel P
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