Question

a sample of air occupies 2.50 L at a temperature of 22.0c . what volume will this sample will this occupy inside a hot air baloon at a temperature of 43.0c assume that the pressure inside the balloon remains constant.

Answer 1

V1/T1= V2/T2 V =volume T= temp (in kelvin unit)

2.5/(22+273)=V2/(43+273)
V2=2.7L

Answer 2

The volume occupied by the air inside the hot balloon is 2.67 L.

Step-by-step explanation:

Initial volume of the balloon =
`V_1= 2.50 L`

Initial temperature of the air inside the balloon
`T_1= 22.0 °C = 295 K`

Final volume of the balloon =
`V_2`

Final temperature of the air inside the balloon =
`T_2= 43.0 °C = 316 K`

Using Charles law:

`(V_1)/(T_1)=(V_2)/(T_2)`

`V_2=(V_1* T_2)/(T_1)=(2.50 L* 316 K)/(295 K)=2.67 L`

The volume occupied by the air inside the hot balloon is 2.67 L.