Question

What's the 32nd term for the sequence 16,10,4,-2

Answer 1

minnus 4 each time
first term is 16
an=a1+d(n-1)
a1=first term
d=common diffferentice

a1=16
d=-4

an=16-4(n-1)
32nd term
n=32

a32=16-4(32-1)
a32=16-4(31)
a32=16-124
a32=-108

the 32nd term is -108