Question

at 25C and 775 torr, Carbon dioxide has a solubility of 0.0347M in water. What is its solubility at 25C and 1270torr?

Answer 1

The solubility of carbon dioxide (CO2) at 25°C and 1270 torr is approximately 0.0536 M.

Step-by-step explanation:

To find the solubility of carbon dioxide (CO2) at 25°C and 1270 torr, we can use the ideal gas law and the given information. The solubility of CO2 at 25°C and 775 torr is given as 0.0347 M. We can set up a proportion to find the solubility at 1270 torr:

(0.0347 M) / (775 torr) = x / (1270 torr)

Solving for x, we find that the solubility of CO2 at 25°C and 1270 torr is approximately 0.0536 M.

Answer 2

Your answer is :
P = K * x where P is partial pressure K is Henry's constant and x is solubility

775 torr = K L·torr/mol * 0.0.0347 mole / liter

K = 775 / 0.0347 = 22334 L·torr/mol

in the second solution we have

1670 = 22334 * x

x = 1670 / 22334

= 0.075 moles CO2 per liter of water.

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