What is the value this?
Good,
Answer = ?
(2Log6 +6log2)/(4log2+log27-log9)
2log6 = 2log(3×2)
2log6 = 2.(Log3 +Log2)
2Log6 = 2Log3+2Log2
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Then,
2Log6+6log2 = 2Log3+2Log2+6log2
= 2Log3+8Log2
= 2(Log3+4Log2)
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We have now:
Log27 = Log(3^3)
Log27 = 3Log3
And
Log9 = Log(3^2)
Log9 = 2Log3
Then us stay....
4log2+log27-log9= 4log2+3log3-2log3
= 4log2 +log3
Soon,
Ans =2( Log3 +4Log2)/(4log2+log3)
We can to cut
Answer = 2