Answer:
(3y - 1)(y - √3)(y + √3)
Explanation:
Factor by grouping.
3y³ - y² - 9y + 3
= (3y³ - y²) - (9y - 3)
= y²(3y - 1) - 3(3y - 1)
= (3y - 1)(y² - 3)
= (3y - 1)(y - √3)(y + √3)
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