Question

How much would a 10th dog have to weight for the average weight in part (a) to be 250 pounds? Explain how you determined your answer.

95, 16, 5, 55, 23, 55 6, 8 53
average i got 35.11
i think the formula is (316+x) 10= 250

Answer 1

(316 + x)/10 = 250

First: Multiply both sides by 10 to begin your isolation of x.

250 * 10 = 2500

Second: Subtract 316 from each side.

2500 - 316 = 2184 lbs.