Question

Two 1.0 kg masses are 4.0 m apart on a frictionless table. Each has 1.0μC of charge. Part A What is the magnitude of the electric force on one of the masses? What is the initial acceleration of each mass if they are released and allowed to move?

Answer 1

The force between two charged particles can be determined using the formula
F = k Q1 Q2 / d²

Using the given values
F = 9 x 10^9 (1.0 x 10^-9)(1.0 x 10^-9) / 4²
F = 5.625 x 10^-10 N

The acceleration is
ma = F
1 (a) = 5.625 x 10^-10
a = 5.625 x 10^-10 m/s²

Answer 2

Force between two charges is given by

`F =(kq_1q_2)/(r^2)`

`F =(9*10^9* 1* 10^(-6)* 1 * 10^(-6))/(4^2)`

`F = 5.625 * 10^(-4) N`

Now in order to find the acceleration of each mass

we can use

F = ma

`5.625 * 10^(-4) = 1 * a`

`a= 5.625 * 10^(-4) m/s^2`