Answer : The parent isotope remain after one half life will be, 100 grams.
Explanation : Given,
Initial mass of the isotope = 200 g
Time taken by the sample, t =

Formula used :

where,
= initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant

Now put all the given values in this formula, we get


Therefore, the parent isotope remain after one half life will be, 100 grams.