Question

What two numbers multiplied give you 100 and added give you 21?

Answer 1

Answer:
`(21)/(2)+(√(41))/(2), (21)/(2)-(√(41))/(2)`

Explanation:

Let the two numbers be x and y.

`x+y=21 \implies y=21-x\\\\xy=100\\\\\therefore x(21-x)=100\\\\21x-x^2 =100\\\\x^2 -21x+100=0\\\\x=(21 \pm √(21^2 -400))/(2)=(21)/(2) \pm (√(41))/(2)`

Answer 2

the answers is -4 and 25