The mass of Helium that it would take to fill the balloon is 1.1277 grams of helium
calculation
mass = density x volume
Density = 1.79 x 10 ⁻⁴ g/ml
Volume = 6.3 L
- convert volume into ml to make the unit uniform
that is 1 L = 1000 ml
6.3 L =? L
by cross multiplication
= ( 6.3 L x 1000 ml) / 1 L = 6300 ml
mass is therefore = 1.79 x 10⁻⁴ g/ml x 6300 ml= 1.1277 grams