Question

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:

2CH4 + 2NH3 + 3O2 -> 2HCN + 6H2O

How many grams of oxygen are required to produce 1 mole of H2O?

a. 48g
b. 16g
c. 32g
d. 24g

Answer 1

16g

Step-by-step explanation:

Got it right on the test.

Answer 2

The grams of oxygen that are required to produce 1 mole of H₂O is 16 g ( answer B)

calculation

2 CH₄ + 2NH₃ +3 O₂ → 2HCN + 6H₂O

step 1: use the mole ratio to find moles of O₂

from equation above the mole ratio of O₂: H₂O is 3:6 therefore the moles of O₂ = 1 mole x3/6 =0.5 moles

step 2: find mass of O₂

mass= moles x molar mass

from periodic table the molar mass of O₂ = 16 x2= 32 g/mol

mass O₂ = 0.5 moles x 32 g/mol = 16 g (answer B)