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A container has 14 yellow chips, 10 blue chips and 12 red chips in it. One chip is randomly chosen from the container, and then a second chip is randomly chosen after replacing the first chip. What is the probability that both chips are red?

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The first probability would be 12/36 because there is a total of 36 chips, and twelve are red (the numerator). IF you reduce this fraction to simplest form, then it would be 1/3.

The second probability would also be 1/3, because the red chip was put back so there are still 36 chips to pick from.

Then, the last step is to multiply 1/3 x 1/3 which would give you 1/9.
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