Question

Use quadratic formula to solve the equation: 12x^2-17x+6 =0

Answer 1

for ax²+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`

so

12x²-17x+6=0
a=12
b=-17
c=6


x=
`(-(-17)+/- √((-17)^2-4(12)(6)) )/(2(12))`
x=
`(17+/- √(289-288) )/(24)`
x=
`(17+/- √(1) )/(24)`
x=
`(17+/- 1)/(32)`
x=
`(17+1)/(32)` or
`(17-1)/(32)`
x=
`(18)/(32)` or
`(16)/(32)`
x=9/16 or 1/2