Question

16x^2+8x+1 =0 use quadratic formula to determine the root. express in fraction form

Answer 1

the answer would be -1/4. go to a web site called math way it will make it easier

Answer 2

for ax²+bx+c=0
x=
`(-b+/- √(b^2-4ac) )/(2a)`

so

16x²+8x+1=0
a=16
b=8
c=1



x=
`(-(8)+/- √((8)^2-4(16)(1)) )/(2(16))`
x=
`(-8+/- √(64-64) )/(32)`
x=
`(-8+/- √(0) )/(32)`
x=
`(-8+/- 0)/(32)`
x=
`(-8)/(32)`
x=-1/4