Question

A 0.100-kilogram apple hangs in a tree 1.50 meters above the ground. Ignoring frictional effects, the total mechanical energy of the apple is _____.

0.00 J
less than 1.47 J but more than 0.00 J
exactly 1.47 J
more than 1.47 J

Answer 1

mgh (.1*9.8*1.5
it would be exactly 1.47

Answer 2

Answer: The total mechanical energy stored in an apple is 1.47 Joules

Step-by-step explanation:

Mass of the apple = 0.100 kg

Height at which apple is hanging = 1.50 m

Force on the apple =
`Mass * g`

Velocity of the apple = 0 m/s

g = acceleration due gravity

Mechanical energy = Potential energy + Kinetic energy

=
`mass* g* height` +
`(1)/(2)mass* (velocity)^2`

`=0.100 kg* 9.8 m/s^2* 1.50 m+(1)/(2)* 0.100 kg* (0 m/s)^2=1.47 Joules`

The total mechanical energy stored in an apple is 1.47 Joules