Question

A running track in the shape of an oval is shown. The ends of the track form semicircles.

What is the perimeter of the inside of the track?

(π = 3.14)

A - 392.00 m
A - 372.22 m
A - 444.44 m
A - 588.88 m

P.S. I attached a file here to look at the oval.

Answer 1

I would think 444.44 ._. Do you go to FLVS? ;-; cause im on the test to xD

Answer 2

The perimeter of inside of the track is
`444.44\ m`

Explanation:

we know that

The perimeter of the oval is equal to the circumference of a circle (two semicircles is equal to one circle) plus the length of
`150\ m` multiplied by
`2`

Find the circumference of a circle

The circumference of a circle is equal to

`C=\pi D`

we have

`D=46\ m`

substitute the values

`C=(3.14)(46)=144.44\ m`

Find the perimeter of the oval

`144.44\ m+2*150\ m=444.44\ m`