Question

a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart

Answer 1

The acceleration of the cart:

a = 0.82 m/s²

Step-by-step explanation:

Given:

m = 2.0 kg

F = 4.0 N

μ = 0.12

g = 9.8 m/s²

___________

a - ?

Friction force:

Ff = μ·m·g

2 Newton's law:

m·a = F - Ff

The acceleration of the cart:

a = ( F - Ff) /m

a = F/m - (μ·m·g) / m

a = F/m - μ·g

a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82 m/s²