159k views
3 votes
I'm in pre algebra, and it's really hard for me, we are doing things with Solving systems of equations by Graphing here is a picture to which I need help on. I did attempt them.

I'm in pre algebra, and it's really hard for me, we are doing things with Solving-example-1
I'm in pre algebra, and it's really hard for me, we are doing things with Solving-example-1
I'm in pre algebra, and it's really hard for me, we are doing things with Solving-example-2
I'm in pre algebra, and it's really hard for me, we are doing things with Solving-example-3
I'm in pre algebra, and it's really hard for me, we are doing things with Solving-example-4
User Mdeora
by
6.7k points

2 Answers

4 votes
To graph y=-3x-4, you need to graph the first point, which would be (0,-4). I know this because of the -4 part in the equation, which represents where the line intersects the y axis.

Then, to find the other points, you have to realize that -3x is the slope of the line.
The slope can also be written as rise/run. Negative 3 is basically -3/1.
So, to find the next point, go down three units from (0,-4) and then one to the right.
Repeat this a few more times.
To get the points that are on the left side of the y axis, go back one and up three from (0,-4). Repeat again.
When you're done, connect all of the points and label the line y=-3x-4.

Do the exact same thing with the next part. If you need me to explain that, too, I'd be glad to.
User Skydan
by
6.5k points
0 votes
This is completely crazy, but we are doing the same thing in my class. So, what you do is because both equation equal y, they equal eachother. Solve the equations, and when you find x, substitute x into one of the equations you worked with. Solve that, and then you have both x and y.
User Josh Randall
by
7.2k points