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A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?
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A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?

User MrJLP
by
5.9k points

1 Answer

5 votes
102.5 km/hr = 28.5 m/s
a = (28.5 - 0) / 10
a = 2.85 m/s²

Resultant force = forward force - friction
ma = F - μmg
F = ma + μmg
F = 905(2.85 + 0.795 x 9.81)
F = 9637.3 N
F = 9600 N
User Sijo Vijayan
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6.2k points
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