Register
A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?
126k views
2 votes
A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?

User MrJLP
by
7.9k points

1 Answer

5 votes
102.5 km/hr = 28.5 m/s
a = (28.5 - 0) / 10
a = 2.85 m/s²

Resultant force = forward force - friction
ma = F - μmg
F = ma + μmg
F = 905(2.85 + 0.795 x 9.81)
F = 9637.3 N
F = 9600 N
User Sijo Vijayan
by
8.3k points
← Prev Question Next Question →

Related questions

User Amorphic
asked Nov 22, 2023 144k views
How much force is required to accelerate a 795 kilogram Lawrence sir speedy by 15 Meters per second squared
Amorphic asked Nov 22, 2023
by Amorphic
7.7k points
1 answer
4 votes
144k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
what is a device that transforms thermal energy to mechanical energy
What is the minimum resistance which can be made using five resistors each of 1/5
Link Copied!