150k views
0 votes
Estimate the number of gallons of gasoline consumed by the total of all automobile drivers in the U.S., per year. Suppose that there are about 3 × 10^8 people in the United States, approximately half of the them have cars, each car drives an average of 12,000 mi per year, and consumes a gallon of gasoline for each 20 mi?

2 Answers

2 votes
3 x 108 is roughly 300 people. Half of them have cars. Half of 300 = 150. 150 x 12000 = 1,800,000 miles driven. Each car gets 20mpg. Solve for the # of gallons consumed.
User Tony J Huang
by
8.1k points
4 votes

Answer:


G = 9 * 10^(10) gallons

Step-by-step explanation:

Total number of people in US is
N_p = 3 * 10^8

Only half of them have cars. So, Number of cars in US


N_C = (N_p)/(2) \\\\N_C = (3 * 10^8)/(2) \\\\N_C = 1.5 * 10^8

Each cars drives 12000 miles, so total distance travelled by all of these cars combined


D = N_C * 12000\\\\D = 1.5 * 10^8 * 12000\\\\D = 1.8 * 10^(12) miles

To travel 20 miles, we need 1 gallon of gasoline

Amount of gasoline required to travel one mile is
(1)/(20) gallons

Amount of gasoline required to cover the distance 'D'.


G = D * (1)/(20) \\\\G = 1.8 * 10^(12) * (1)/(20) \\\\G = 9 * 10^(10) gallons

Amount of gasoline required to cover the distance 'D'.


G = D * (1)/(20) \\\\G = 1.8 * 10^(12) * (1)/(20) \\\\G = 9 * 10^(10) gallons

User Sanorita
by
8.5k points