1) Value of the tractor, using the model f(x) = 15,000*(0.90)^x, for x = 5
f(5) = 15,000*(0,90)^5 = 15,000*0.59049 = 8,857.35
2) Value of the truck, using the table g(x) for x = 5
g(5) = 7,414.80
3) difference f(5) - g(5) = 8,857.35 - 7,414.80 = 1,442.55
Answer: 1, 442.55